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(1.00*10^-3)*x=0.0585
We move all terms to the left:
(1.00*10^-3)*x-(0.0585)=0
We add all the numbers together, and all the variables
(1.00*10^-3)*x-0.0585=0
We multiply parentheses
10x^2-3x-0.0585=0
a = 10; b = -3; c = -0.0585;
Δ = b2-4ac
Δ = -32-4·10·(-0.0585)
Δ = 11.34
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-\sqrt{11.34}}{2*10}=\frac{3-\sqrt{11.34}}{20} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+\sqrt{11.34}}{2*10}=\frac{3+\sqrt{11.34}}{20} $
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